We have established the a simple harmonic oscillator moves in a periodic
motion... therefore we can say that it has an angular acceleration (ω).
ω = 2π/T = 2πf
And when we substitute this into the trig. equations we saw earlier, we find that:
D(t) = A sin (ωt)
or
D(t) = A sin (2πf * t)
Where: D(t) = the displacement of the oscillator at time, t (m)
A = the maximum displacement
of the oscillator (m)
f = frequency (Hz)
t = time (s)
These equations allows us to solve most SHM problems.
